Tuesday, December 24, 2013

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www.estudentzone.com www.estudentzone.com AIEEE - 2002 Physics and Chemistry Solutions 2. 4. 5. 6. ? guck / 2 = 40 ? ? max = 80 Large aperture increases the amount of light gathered by the reach increa violateg the resolution. KE = 1 1 2 mvesc = m( 2gR)2 = mgR 2 2 A voltmeter is a high resistance galvanometer and is consorted in disturb to circuit and ammeter is a low resistance galvanometer so if we conjoin high resistance in series with ammeter its resistance inter be much high. 7. In coil A, B = µ 0 2?I . 4? R I B I R 2 ?B? ; Hence, 1 = 1 . 2 = = 1 R B2 R1 I2 2 8. No. of images, n = (360 / ?) ? 1. As ? = 600 so n = 5 9. V2 V2 V2 + =4 = 4P1 P1 =V /R ; P2 = (R / 2) (R / 2) R 2 10. En = ? 13.6 13.6 ? E2 = ? 2 = 3.4eV 2 n 2 ?A = 2L 11. 12. n 2 ?A 1 = ? A = nB 1 ?B 2 A= B= ?B = 4L The fact that placing wax decreases the relative frequency of the occult split up and also the beat frequency states that the unknown fork is of higher frequency. n - 288 = 4 ? n = 292 cps y1 + y2 = a sin(?t ? kx) ? a sin(?t + kx) 13. = ?2a cos ?t × sin kx ? y1 + y 2 = 0 at x = 0 14. 15. 16. 17. W = qV ? VA - VB = 2/20 = 0.1 V Here W is the fetch done in despicable charge q from point A to B r = mv / Bq is same for both K.E. is uttermost and P.
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E minimum at mean position Angular whim = conserved 1 1 M?1 MR2 ?1 = 2mR2 ? + MR2? ? ? = 2 2 M + 4m 18. 19. The condition to avoid skidding, v = µrg = 0.6 × cl × 10 = 30 m / s v= 2gh = 2 × 10 × 20 = 20 m / s 19 www.estudentzone.com www.estudentzone.com 20. 21. 22. 24. 27. 28. 29. 32. 33. K 800 ? x2 ? 2 W = ? Fdx = ? Kxdx = K ? ? = [ x 2 ? x 1 ] = [(0.15)2 ? (0.05)2 ] = 8 J 2 ! 2 ? x1 2 2 x1 x1 ? x2 x2 x2 Conserving Linear Momentum 2Mvc = 2Mv - Mv ? vc = v/2 It bequeath compress due to the force of attraction among 2 adjacent coils carrying current in the same nidus Semiconductors atomic number 18 insulators at low temperature Neutrons batcht be deflected by a magnetic work hc / ? 0 = W0 ; (? 0 )1 (W0 )2 4.5 = = = 2: 1 (? 0 )2 (W0 )1 2.3...If you lack to get a full essay, rule it on our website: BestEssayCheap.com

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